gtsocial-umbx

rect.go (24902B)

---

 // Copyright 2014 Google Inc. All rights reserved.
 //
 // Licensed under the Apache License, Version 2.0 (the "License");
 // you may not use this file except in compliance with the License.
 // You may obtain a copy of the License at
 //
 //     http://www.apache.org/licenses/LICENSE-2.0
 //
 // Unless required by applicable law or agreed to in writing, software
 // distributed under the License is distributed on an "AS IS" BASIS,
 // WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 // See the License for the specific language governing permissions and
 // limitations under the License.
 
 package s2
 
 import (
 	"fmt"
 	"io"
 	"math"
 
 	"github.com/golang/geo/r1"
 	"github.com/golang/geo/r3"
 	"github.com/golang/geo/s1"
 )
 
 // Rect represents a closed latitude-longitude rectangle.
 type Rect struct {
 	Lat r1.Interval
 	Lng s1.Interval
 }
 
 var (
 	validRectLatRange = r1.Interval{-math.Pi / 2, math.Pi / 2}
 	validRectLngRange = s1.FullInterval()
 )
 
 // EmptyRect returns the empty rectangle.
 func EmptyRect() Rect { return Rect{r1.EmptyInterval(), s1.EmptyInterval()} }
 
 // FullRect returns the full rectangle.
 func FullRect() Rect { return Rect{validRectLatRange, validRectLngRange} }
 
 // RectFromLatLng constructs a rectangle containing a single point p.
 func RectFromLatLng(p LatLng) Rect {
 	return Rect{
 		Lat: r1.Interval{p.Lat.Radians(), p.Lat.Radians()},
 		Lng: s1.Interval{p.Lng.Radians(), p.Lng.Radians()},
 	}
 }
 
 // RectFromCenterSize constructs a rectangle with the given size and center.
 // center needs to be normalized, but size does not. The latitude
 // interval of the result is clamped to [-90,90] degrees, and the longitude
 // interval of the result is FullRect() if and only if the longitude size is
 // 360 degrees or more.
 //
 // Examples of clamping (in degrees):
 //   center=(80,170),  size=(40,60)   -> lat=[60,90],   lng=[140,-160]
 //   center=(10,40),   size=(210,400) -> lat=[-90,90],  lng=[-180,180]
 //   center=(-90,180), size=(20,50)   -> lat=[-90,-80], lng=[155,-155]
 func RectFromCenterSize(center, size LatLng) Rect {
 	half := LatLng{size.Lat / 2, size.Lng / 2}
 	return RectFromLatLng(center).expanded(half)
 }
 
 // IsValid returns true iff the rectangle is valid.
 // This requires Lat ⊆ [-π/2,π/2] and Lng ⊆ [-π,π], and Lat = ∅ iff Lng = ∅
 func (r Rect) IsValid() bool {
 	return math.Abs(r.Lat.Lo) <= math.Pi/2 &&
 		math.Abs(r.Lat.Hi) <= math.Pi/2 &&
 		r.Lng.IsValid() &&
 		r.Lat.IsEmpty() == r.Lng.IsEmpty()
 }
 
 // IsEmpty reports whether the rectangle is empty.
 func (r Rect) IsEmpty() bool { return r.Lat.IsEmpty() }
 
 // IsFull reports whether the rectangle is full.
 func (r Rect) IsFull() bool { return r.Lat.Equal(validRectLatRange) && r.Lng.IsFull() }
 
 // IsPoint reports whether the rectangle is a single point.
 func (r Rect) IsPoint() bool { return r.Lat.Lo == r.Lat.Hi && r.Lng.Lo == r.Lng.Hi }
 
 // Vertex returns the i-th vertex of the rectangle (i = 0,1,2,3) in CCW order
 // (lower left, lower right, upper right, upper left).
 func (r Rect) Vertex(i int) LatLng {
 	var lat, lng float64
 
 	switch i {
 	case 0:
 		lat = r.Lat.Lo
 		lng = r.Lng.Lo
 	case 1:
 		lat = r.Lat.Lo
 		lng = r.Lng.Hi
 	case 2:
 		lat = r.Lat.Hi
 		lng = r.Lng.Hi
 	case 3:
 		lat = r.Lat.Hi
 		lng = r.Lng.Lo
 	}
 	return LatLng{s1.Angle(lat) * s1.Radian, s1.Angle(lng) * s1.Radian}
 }
 
 // Lo returns one corner of the rectangle.
 func (r Rect) Lo() LatLng {
 	return LatLng{s1.Angle(r.Lat.Lo) * s1.Radian, s1.Angle(r.Lng.Lo) * s1.Radian}
 }
 
 // Hi returns the other corner of the rectangle.
 func (r Rect) Hi() LatLng {
 	return LatLng{s1.Angle(r.Lat.Hi) * s1.Radian, s1.Angle(r.Lng.Hi) * s1.Radian}
 }
 
 // Center returns the center of the rectangle.
 func (r Rect) Center() LatLng {
 	return LatLng{s1.Angle(r.Lat.Center()) * s1.Radian, s1.Angle(r.Lng.Center()) * s1.Radian}
 }
 
 // Size returns the size of the Rect.
 func (r Rect) Size() LatLng {
 	return LatLng{s1.Angle(r.Lat.Length()) * s1.Radian, s1.Angle(r.Lng.Length()) * s1.Radian}
 }
 
 // Area returns the surface area of the Rect.
 func (r Rect) Area() float64 {
 	if r.IsEmpty() {
 		return 0
 	}
 	capDiff := math.Abs(math.Sin(r.Lat.Hi) - math.Sin(r.Lat.Lo))
 	return r.Lng.Length() * capDiff
 }
 
 // AddPoint increases the size of the rectangle to include the given point.
 func (r Rect) AddPoint(ll LatLng) Rect {
 	if !ll.IsValid() {
 		return r
 	}
 	return Rect{
 		Lat: r.Lat.AddPoint(ll.Lat.Radians()),
 		Lng: r.Lng.AddPoint(ll.Lng.Radians()),
 	}
 }
 
 // expanded returns a rectangle that has been expanded by margin.Lat on each side
 // in the latitude direction, and by margin.Lng on each side in the longitude
 // direction. If either margin is negative, then it shrinks the rectangle on
 // the corresponding sides instead. The resulting rectangle may be empty.
 //
 // The latitude-longitude space has the topology of a cylinder. Longitudes
 // "wrap around" at +/-180 degrees, while latitudes are clamped to range [-90, 90].
 // This means that any expansion (positive or negative) of the full longitude range
 // remains full (since the "rectangle" is actually a continuous band around the
 // cylinder), while expansion of the full latitude range remains full only if the
 // margin is positive.
 //
 // If either the latitude or longitude interval becomes empty after
 // expansion by a negative margin, the result is empty.
 //
 // Note that if an expanded rectangle contains a pole, it may not contain
 // all possible lat/lng representations of that pole, e.g., both points [π/2,0]
 // and [π/2,1] represent the same pole, but they might not be contained by the
 // same Rect.
 //
 // If you are trying to grow a rectangle by a certain distance on the
 // sphere (e.g. 5km), refer to the ExpandedByDistance() C++ method implementation
 // instead.
 func (r Rect) expanded(margin LatLng) Rect {
 	lat := r.Lat.Expanded(margin.Lat.Radians())
 	lng := r.Lng.Expanded(margin.Lng.Radians())
 
 	if lat.IsEmpty() || lng.IsEmpty() {
 		return EmptyRect()
 	}
 
 	return Rect{
 		Lat: lat.Intersection(validRectLatRange),
 		Lng: lng,
 	}
 }
 
 func (r Rect) String() string { return fmt.Sprintf("[Lo%v, Hi%v]", r.Lo(), r.Hi()) }
 
 // PolarClosure returns the rectangle unmodified if it does not include either pole.
 // If it includes either pole, PolarClosure returns an expansion of the rectangle along
 // the longitudinal range to include all possible representations of the contained poles.
 func (r Rect) PolarClosure() Rect {
 	if r.Lat.Lo == -math.Pi/2 || r.Lat.Hi == math.Pi/2 {
 		return Rect{r.Lat, s1.FullInterval()}
 	}
 	return r
 }
 
 // Union returns the smallest Rect containing the union of this rectangle and the given rectangle.
 func (r Rect) Union(other Rect) Rect {
 	return Rect{
 		Lat: r.Lat.Union(other.Lat),
 		Lng: r.Lng.Union(other.Lng),
 	}
 }
 
 // Intersection returns the smallest rectangle containing the intersection of
 // this rectangle and the given rectangle. Note that the region of intersection
 // may consist of two disjoint rectangles, in which case a single rectangle
 // spanning both of them is returned.
 func (r Rect) Intersection(other Rect) Rect {
 	lat := r.Lat.Intersection(other.Lat)
 	lng := r.Lng.Intersection(other.Lng)
 
 	if lat.IsEmpty() || lng.IsEmpty() {
 		return EmptyRect()
 	}
 	return Rect{lat, lng}
 }
 
 // Intersects reports whether this rectangle and the other have any points in common.
 func (r Rect) Intersects(other Rect) bool {
 	return r.Lat.Intersects(other.Lat) && r.Lng.Intersects(other.Lng)
 }
 
 // CapBound returns a cap that contains Rect.
 func (r Rect) CapBound() Cap {
 	// We consider two possible bounding caps, one whose axis passes
 	// through the center of the lat-long rectangle and one whose axis
 	// is the north or south pole.  We return the smaller of the two caps.
 
 	if r.IsEmpty() {
 		return EmptyCap()
 	}
 
 	var poleZ, poleAngle float64
 	if r.Lat.Hi+r.Lat.Lo < 0 {
 		// South pole axis yields smaller cap.
 		poleZ = -1
 		poleAngle = math.Pi/2 + r.Lat.Hi
 	} else {
 		poleZ = 1
 		poleAngle = math.Pi/2 - r.Lat.Lo
 	}
 	poleCap := CapFromCenterAngle(Point{r3.Vector{0, 0, poleZ}}, s1.Angle(poleAngle)*s1.Radian)
 
 	// For bounding rectangles that span 180 degrees or less in longitude, the
 	// maximum cap size is achieved at one of the rectangle vertices.  For
 	// rectangles that are larger than 180 degrees, we punt and always return a
 	// bounding cap centered at one of the two poles.
 	if math.Remainder(r.Lng.Hi-r.Lng.Lo, 2*math.Pi) >= 0 && r.Lng.Hi-r.Lng.Lo < 2*math.Pi {
 		midCap := CapFromPoint(PointFromLatLng(r.Center())).AddPoint(PointFromLatLng(r.Lo())).AddPoint(PointFromLatLng(r.Hi()))
 		if midCap.Height() < poleCap.Height() {
 			return midCap
 		}
 	}
 	return poleCap
 }
 
 // RectBound returns itself.
 func (r Rect) RectBound() Rect {
 	return r
 }
 
 // Contains reports whether this Rect contains the other Rect.
 func (r Rect) Contains(other Rect) bool {
 	return r.Lat.ContainsInterval(other.Lat) && r.Lng.ContainsInterval(other.Lng)
 }
 
 // ContainsCell reports whether the given Cell is contained by this Rect.
 func (r Rect) ContainsCell(c Cell) bool {
 	// A latitude-longitude rectangle contains a cell if and only if it contains
 	// the cell's bounding rectangle. This test is exact from a mathematical
 	// point of view, assuming that the bounds returned by Cell.RectBound()
 	// are tight. However, note that there can be a loss of precision when
 	// converting between representations -- for example, if an s2.Cell is
 	// converted to a polygon, the polygon's bounding rectangle may not contain
 	// the cell's bounding rectangle. This has some slightly unexpected side
 	// effects; for instance, if one creates an s2.Polygon from an s2.Cell, the
 	// polygon will contain the cell, but the polygon's bounding box will not.
 	return r.Contains(c.RectBound())
 }
 
 // ContainsLatLng reports whether the given LatLng is within the Rect.
 func (r Rect) ContainsLatLng(ll LatLng) bool {
 	if !ll.IsValid() {
 		return false
 	}
 	return r.Lat.Contains(ll.Lat.Radians()) && r.Lng.Contains(ll.Lng.Radians())
 }
 
 // ContainsPoint reports whether the given Point is within the Rect.
 func (r Rect) ContainsPoint(p Point) bool {
 	return r.ContainsLatLng(LatLngFromPoint(p))
 }
 
 // CellUnionBound computes a covering of the Rect.
 func (r Rect) CellUnionBound() []CellID {
 	return r.CapBound().CellUnionBound()
 }
 
 // intersectsLatEdge reports whether the edge AB intersects the given edge of constant
 // latitude. Requires the points to have unit length.
 func intersectsLatEdge(a, b Point, lat s1.Angle, lng s1.Interval) bool {
 	// Unfortunately, lines of constant latitude are curves on
 	// the sphere. They can intersect a straight edge in 0, 1, or 2 points.
 
 	// First, compute the normal to the plane AB that points vaguely north.
 	z := Point{a.PointCross(b).Normalize()}
 	if z.Z < 0 {
 		z = Point{z.Mul(-1)}
 	}
 
 	// Extend this to an orthonormal frame (x,y,z) where x is the direction
 	// where the great circle through AB achieves its maximium latitude.
 	y := Point{z.PointCross(PointFromCoords(0, 0, 1)).Normalize()}
 	x := y.Cross(z.Vector)
 
 	// Compute the angle "theta" from the x-axis (in the x-y plane defined
 	// above) where the great circle intersects the given line of latitude.
 	sinLat := math.Sin(float64(lat))
 	if math.Abs(sinLat) >= x.Z {
 		// The great circle does not reach the given latitude.
 		return false
 	}
 
 	cosTheta := sinLat / x.Z
 	sinTheta := math.Sqrt(1 - cosTheta*cosTheta)
 	theta := math.Atan2(sinTheta, cosTheta)
 
 	// The candidate intersection points are located +/- theta in the x-y
 	// plane. For an intersection to be valid, we need to check that the
 	// intersection point is contained in the interior of the edge AB and
 	// also that it is contained within the given longitude interval "lng".
 
 	// Compute the range of theta values spanned by the edge AB.
 	abTheta := s1.IntervalFromPointPair(
 		math.Atan2(a.Dot(y.Vector), a.Dot(x)),
 		math.Atan2(b.Dot(y.Vector), b.Dot(x)))
 
 	if abTheta.Contains(theta) {
 		// Check if the intersection point is also in the given lng interval.
 		isect := x.Mul(cosTheta).Add(y.Mul(sinTheta))
 		if lng.Contains(math.Atan2(isect.Y, isect.X)) {
 			return true
 		}
 	}
 
 	if abTheta.Contains(-theta) {
 		// Check if the other intersection point is also in the given lng interval.
 		isect := x.Mul(cosTheta).Sub(y.Mul(sinTheta))
 		if lng.Contains(math.Atan2(isect.Y, isect.X)) {
 			return true
 		}
 	}
 	return false
 }
 
 // intersectsLngEdge reports whether the edge AB intersects the given edge of constant
 // longitude. Requires the points to have unit length.
 func intersectsLngEdge(a, b Point, lat r1.Interval, lng s1.Angle) bool {
 	// The nice thing about edges of constant longitude is that
 	// they are straight lines on the sphere (geodesics).
 	return CrossingSign(a, b, PointFromLatLng(LatLng{s1.Angle(lat.Lo), lng}),
 		PointFromLatLng(LatLng{s1.Angle(lat.Hi), lng})) == Cross
 }
 
 // IntersectsCell reports whether this rectangle intersects the given cell. This is an
 // exact test and may be fairly expensive.
 func (r Rect) IntersectsCell(c Cell) bool {
 	// First we eliminate the cases where one region completely contains the
 	// other. Once these are disposed of, then the regions will intersect
 	// if and only if their boundaries intersect.
 	if r.IsEmpty() {
 		return false
 	}
 	if r.ContainsPoint(Point{c.id.rawPoint()}) {
 		return true
 	}
 	if c.ContainsPoint(PointFromLatLng(r.Center())) {
 		return true
 	}
 
 	// Quick rejection test (not required for correctness).
 	if !r.Intersects(c.RectBound()) {
 		return false
 	}
 
 	// Precompute the cell vertices as points and latitude-longitudes. We also
 	// check whether the Cell contains any corner of the rectangle, or
 	// vice-versa, since the edge-crossing tests only check the edge interiors.
 	vertices := [4]Point{}
 	latlngs := [4]LatLng{}
 
 	for i := range vertices {
 		vertices[i] = c.Vertex(i)
 		latlngs[i] = LatLngFromPoint(vertices[i])
 		if r.ContainsLatLng(latlngs[i]) {
 			return true
 		}
 		if c.ContainsPoint(PointFromLatLng(r.Vertex(i))) {
 			return true
 		}
 	}
 
 	// Now check whether the boundaries intersect. Unfortunately, a
 	// latitude-longitude rectangle does not have straight edges: two edges
 	// are curved, and at least one of them is concave.
 	for i := range vertices {
 		edgeLng := s1.IntervalFromEndpoints(latlngs[i].Lng.Radians(), latlngs[(i+1)&3].Lng.Radians())
 		if !r.Lng.Intersects(edgeLng) {
 			continue
 		}
 
 		a := vertices[i]
 		b := vertices[(i+1)&3]
 		if edgeLng.Contains(r.Lng.Lo) && intersectsLngEdge(a, b, r.Lat, s1.Angle(r.Lng.Lo)) {
 			return true
 		}
 		if edgeLng.Contains(r.Lng.Hi) && intersectsLngEdge(a, b, r.Lat, s1.Angle(r.Lng.Hi)) {
 			return true
 		}
 		if intersectsLatEdge(a, b, s1.Angle(r.Lat.Lo), r.Lng) {
 			return true
 		}
 		if intersectsLatEdge(a, b, s1.Angle(r.Lat.Hi), r.Lng) {
 			return true
 		}
 	}
 	return false
 }
 
 // Encode encodes the Rect.
 func (r Rect) Encode(w io.Writer) error {
 	e := &encoder{w: w}
 	r.encode(e)
 	return e.err
 }
 
 func (r Rect) encode(e *encoder) {
 	e.writeInt8(encodingVersion)
 	e.writeFloat64(r.Lat.Lo)
 	e.writeFloat64(r.Lat.Hi)
 	e.writeFloat64(r.Lng.Lo)
 	e.writeFloat64(r.Lng.Hi)
 }
 
 // Decode decodes a rectangle.
 func (r *Rect) Decode(rd io.Reader) error {
 	d := &decoder{r: asByteReader(rd)}
 	r.decode(d)
 	return d.err
 }
 
 func (r *Rect) decode(d *decoder) {
 	if version := d.readUint8(); int8(version) != encodingVersion && d.err == nil {
 		d.err = fmt.Errorf("can't decode version %d; my version: %d", version, encodingVersion)
 		return
 	}
 	r.Lat.Lo = d.readFloat64()
 	r.Lat.Hi = d.readFloat64()
 	r.Lng.Lo = d.readFloat64()
 	r.Lng.Hi = d.readFloat64()
 	return
 }
 
 // DistanceToLatLng returns the minimum distance (measured along the surface of the sphere)
 // from a given point to the rectangle (both its boundary and its interior).
 // If r is empty, the result is meaningless.
 // The latlng must be valid.
 func (r Rect) DistanceToLatLng(ll LatLng) s1.Angle {
 	if r.Lng.Contains(float64(ll.Lng)) {
 		return maxAngle(0, ll.Lat-s1.Angle(r.Lat.Hi), s1.Angle(r.Lat.Lo)-ll.Lat)
 	}
 
 	i := s1.IntervalFromEndpoints(r.Lng.Hi, r.Lng.ComplementCenter())
 	rectLng := r.Lng.Lo
 	if i.Contains(float64(ll.Lng)) {
 		rectLng = r.Lng.Hi
 	}
 
 	lo := LatLng{s1.Angle(r.Lat.Lo) * s1.Radian, s1.Angle(rectLng) * s1.Radian}
 	hi := LatLng{s1.Angle(r.Lat.Hi) * s1.Radian, s1.Angle(rectLng) * s1.Radian}
 	return DistanceFromSegment(PointFromLatLng(ll), PointFromLatLng(lo), PointFromLatLng(hi))
 }
 
 // DirectedHausdorffDistance returns the directed Hausdorff distance (measured along the
 // surface of the sphere) to the given Rect. The directed Hausdorff
 // distance from rectangle A to rectangle B is given by
 //     h(A, B) = max_{p in A} min_{q in B} d(p, q).
 func (r Rect) DirectedHausdorffDistance(other Rect) s1.Angle {
 	if r.IsEmpty() {
 		return 0 * s1.Radian
 	}
 	if other.IsEmpty() {
 		return math.Pi * s1.Radian
 	}
 
 	lng := r.Lng.DirectedHausdorffDistance(other.Lng)
 	return directedHausdorffDistance(lng, r.Lat, other.Lat)
 }
 
 // HausdorffDistance returns the undirected Hausdorff distance (measured along the
 // surface of the sphere) to the given Rect.
 // The Hausdorff distance between rectangle A and rectangle B is given by
 //     H(A, B) = max{h(A, B), h(B, A)}.
 func (r Rect) HausdorffDistance(other Rect) s1.Angle {
 	return maxAngle(r.DirectedHausdorffDistance(other),
 		other.DirectedHausdorffDistance(r))
 }
 
 // ApproxEqual reports whether the latitude and longitude intervals of the two rectangles
 // are the same up to a small tolerance.
 func (r Rect) ApproxEqual(other Rect) bool {
 	return r.Lat.ApproxEqual(other.Lat) && r.Lng.ApproxEqual(other.Lng)
 }
 
 // directedHausdorffDistance returns the directed Hausdorff distance
 // from one longitudinal edge spanning latitude range 'a' to the other
 // longitudinal edge spanning latitude range 'b', with their longitudinal
 // difference given by 'lngDiff'.
 func directedHausdorffDistance(lngDiff s1.Angle, a, b r1.Interval) s1.Angle {
 	// By symmetry, we can assume a's longitude is 0 and b's longitude is
 	// lngDiff. Call b's two endpoints bLo and bHi. Let H be the hemisphere
 	// containing a and delimited by the longitude line of b. The Voronoi diagram
 	// of b on H has three edges (portions of great circles) all orthogonal to b
 	// and meeting at bLo cross bHi.
 	// E1: (bLo, bLo cross bHi)
 	// E2: (bHi, bLo cross bHi)
 	// E3: (-bMid, bLo cross bHi), where bMid is the midpoint of b
 	//
 	// They subdivide H into three Voronoi regions. Depending on how longitude 0
 	// (which contains edge a) intersects these regions, we distinguish two cases:
 	// Case 1: it intersects three regions. This occurs when lngDiff <= π/2.
 	// Case 2: it intersects only two regions. This occurs when lngDiff > π/2.
 	//
 	// In the first case, the directed Hausdorff distance to edge b can only be
 	// realized by the following points on a:
 	// A1: two endpoints of a.
 	// A2: intersection of a with the equator, if b also intersects the equator.
 	//
 	// In the second case, the directed Hausdorff distance to edge b can only be
 	// realized by the following points on a:
 	// B1: two endpoints of a.
 	// B2: intersection of a with E3
 	// B3: farthest point from bLo to the interior of D, and farthest point from
 	//     bHi to the interior of U, if any, where D (resp. U) is the portion
 	//     of edge a below (resp. above) the intersection point from B2.
 
 	if lngDiff < 0 {
 		panic("impossible: negative lngDiff")
 	}
 	if lngDiff > math.Pi {
 		panic("impossible: lngDiff > Pi")
 	}
 
 	if lngDiff == 0 {
 		return s1.Angle(a.DirectedHausdorffDistance(b))
 	}
 
 	// Assumed longitude of b.
 	bLng := lngDiff
 	// Two endpoints of b.
 	bLo := PointFromLatLng(LatLng{s1.Angle(b.Lo), bLng})
 	bHi := PointFromLatLng(LatLng{s1.Angle(b.Hi), bLng})
 
 	// Cases A1 and B1.
 	aLo := PointFromLatLng(LatLng{s1.Angle(a.Lo), 0})
 	aHi := PointFromLatLng(LatLng{s1.Angle(a.Hi), 0})
 	maxDistance := maxAngle(
 		DistanceFromSegment(aLo, bLo, bHi),
 		DistanceFromSegment(aHi, bLo, bHi))
 
 	if lngDiff <= math.Pi/2 {
 		// Case A2.
 		if a.Contains(0) && b.Contains(0) {
 			maxDistance = maxAngle(maxDistance, lngDiff)
 		}
 		return maxDistance
 	}
 
 	// Case B2.
 	p := bisectorIntersection(b, bLng)
 	pLat := LatLngFromPoint(p).Lat
 	if a.Contains(float64(pLat)) {
 		maxDistance = maxAngle(maxDistance, p.Angle(bLo.Vector))
 	}
 
 	// Case B3.
 	if pLat > s1.Angle(a.Lo) {
 		intDist, ok := interiorMaxDistance(r1.Interval{a.Lo, math.Min(float64(pLat), a.Hi)}, bLo)
 		if ok {
 			maxDistance = maxAngle(maxDistance, intDist)
 		}
 	}
 	if pLat < s1.Angle(a.Hi) {
 		intDist, ok := interiorMaxDistance(r1.Interval{math.Max(float64(pLat), a.Lo), a.Hi}, bHi)
 		if ok {
 			maxDistance = maxAngle(maxDistance, intDist)
 		}
 	}
 
 	return maxDistance
 }
 
 // interiorMaxDistance returns the max distance from a point b to the segment spanning latitude range
 // aLat on longitude 0 if the max occurs in the interior of aLat. Otherwise, returns (0, false).
 func interiorMaxDistance(aLat r1.Interval, b Point) (a s1.Angle, ok bool) {
 	// Longitude 0 is in the y=0 plane. b.X >= 0 implies that the maximum
 	// does not occur in the interior of aLat.
 	if aLat.IsEmpty() || b.X >= 0 {
 		return 0, false
 	}
 
 	// Project b to the y=0 plane. The antipodal of the normalized projection is
 	// the point at which the maxium distance from b occurs, if it is contained
 	// in aLat.
 	intersectionPoint := PointFromCoords(-b.X, 0, -b.Z)
 	if !aLat.InteriorContains(float64(LatLngFromPoint(intersectionPoint).Lat)) {
 		return 0, false
 	}
 	return b.Angle(intersectionPoint.Vector), true
 }
 
 // bisectorIntersection return the intersection of longitude 0 with the bisector of an edge
 // on longitude 'lng' and spanning latitude range 'lat'.
 func bisectorIntersection(lat r1.Interval, lng s1.Angle) Point {
 	lng = s1.Angle(math.Abs(float64(lng)))
 	latCenter := s1.Angle(lat.Center())
 
 	// A vector orthogonal to the bisector of the given longitudinal edge.
 	orthoBisector := LatLng{latCenter - math.Pi/2, lng}
 	if latCenter < 0 {
 		orthoBisector = LatLng{-latCenter - math.Pi/2, lng - math.Pi}
 	}
 
 	// A vector orthogonal to longitude 0.
 	orthoLng := Point{r3.Vector{0, -1, 0}}
 
 	return orthoLng.PointCross(PointFromLatLng(orthoBisector))
 }
 
 // Centroid returns the true centroid of the given Rect multiplied by its
 // surface area. The result is not unit length, so you may want to normalize it.
 // Note that in general the centroid is *not* at the center of the rectangle, and
 // in fact it may not even be contained by the rectangle. (It is the "center of
 // mass" of the rectangle viewed as subset of the unit sphere, i.e. it is the
 // point in space about which this curved shape would rotate.)
 //
 // The reason for multiplying the result by the rectangle area is to make it
 // easier to compute the centroid of more complicated shapes. The centroid
 // of a union of disjoint regions can be computed simply by adding their
 // Centroid results.
 func (r Rect) Centroid() Point {
 	// When a sphere is divided into slices of constant thickness by a set
 	// of parallel planes, all slices have the same surface area. This
 	// implies that the z-component of the centroid is simply the midpoint
 	// of the z-interval spanned by the Rect.
 	//
 	// Similarly, it is easy to see that the (x,y) of the centroid lies in
 	// the plane through the midpoint of the rectangle's longitude interval.
 	// We only need to determine the distance "d" of this point from the
 	// z-axis.
 	//
 	// Let's restrict our attention to a particular z-value. In this
 	// z-plane, the Rect is a circular arc. The centroid of this arc
 	// lies on a radial line through the midpoint of the arc, and at a
 	// distance from the z-axis of
 	//
 	//     r * (sin(alpha) / alpha)
 	//
 	// where r = sqrt(1-z^2) is the radius of the arc, and "alpha" is half
 	// of the arc length (i.e., the arc covers longitudes [-alpha, alpha]).
 	//
 	// To find the centroid distance from the z-axis for the entire
 	// rectangle, we just need to integrate over the z-interval. This gives
 	//
 	//    d = Integrate[sqrt(1-z^2)*sin(alpha)/alpha, z1..z2] / (z2 - z1)
 	//
 	// where [z1, z2] is the range of z-values covered by the rectangle.
 	// This simplifies to
 	//
 	//    d = sin(alpha)/(2*alpha*(z2-z1))*(z2*r2 - z1*r1 + theta2 - theta1)
 	//
 	// where [theta1, theta2] is the latitude interval, z1=sin(theta1),
 	// z2=sin(theta2), r1=cos(theta1), and r2=cos(theta2).
 	//
 	// Finally, we want to return not the centroid itself, but the centroid
 	// scaled by the area of the rectangle. The area of the rectangle is
 	//
 	//    A = 2 * alpha * (z2 - z1)
 	//
 	// which fortunately appears in the denominator of "d".
 
 	if r.IsEmpty() {
 		return Point{}
 	}
 
 	z1 := math.Sin(r.Lat.Lo)
 	z2 := math.Sin(r.Lat.Hi)
 	r1 := math.Cos(r.Lat.Lo)
 	r2 := math.Cos(r.Lat.Hi)
 
 	alpha := 0.5 * r.Lng.Length()
 	r0 := math.Sin(alpha) * (r2*z2 - r1*z1 + r.Lat.Length())
 	lng := r.Lng.Center()
 	z := alpha * (z2 + z1) * (z2 - z1) // scaled by the area
 
 	return Point{r3.Vector{r0 * math.Cos(lng), r0 * math.Sin(lng), z}}
 }
 
 // BUG: The major differences from the C++ version are:
 //  - Get*Distance, Vertex, InteriorContains(LatLng|Rect|Point)